x^2+7x+2x+36=180

Solution for x^2+7x+2x+36=180 equation:

x^2+7x+2x+36=180

We move all terms to the left:

x^2+7x+2x+36-(180)=0

We add all the numbers together, and all the variables

x^2+9x-144=0

a = 1; b = 9; c = -144;
Δ = b2-4ac
Δ = 92-4·1·(-144)
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{73}}{2*1}=\frac{-9-3\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{73}}{2*1}=\frac{-9+3\sqrt{73}}{2}
$